z^3-3iz^2-3z+i=1

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Solution for z^3-3iz^2-3z+i=1 equation:


Simplifying
z3 + -3iz2 + -3z + i = 1

Reorder the terms:
i + -3iz2 + -3z + z3 = 1

Solving
i + -3iz2 + -3z + z3 = 1

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '3z' to each side of the equation.
i + -3iz2 + -3z + 3z + z3 = 1 + 3z

Combine like terms: -3z + 3z = 0
i + -3iz2 + 0 + z3 = 1 + 3z
i + -3iz2 + z3 = 1 + 3z

Add '-1z3' to each side of the equation.
i + -3iz2 + z3 + -1z3 = 1 + 3z + -1z3

Combine like terms: z3 + -1z3 = 0
i + -3iz2 + 0 = 1 + 3z + -1z3
i + -3iz2 = 1 + 3z + -1z3

Reorder the terms:
-1 + i + -3iz2 + -3z + z3 = 1 + 3z + -1z3 + -1 + -3z + z3

Reorder the terms:
-1 + i + -3iz2 + -3z + z3 = 1 + -1 + 3z + -3z + -1z3 + z3

Combine like terms: 1 + -1 = 0
-1 + i + -3iz2 + -3z + z3 = 0 + 3z + -3z + -1z3 + z3
-1 + i + -3iz2 + -3z + z3 = 3z + -3z + -1z3 + z3

Combine like terms: 3z + -3z = 0
-1 + i + -3iz2 + -3z + z3 = 0 + -1z3 + z3
-1 + i + -3iz2 + -3z + z3 = -1z3 + z3

Combine like terms: -1z3 + z3 = 0
-1 + i + -3iz2 + -3z + z3 = 0

The solution to this equation could not be determined.

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